Calculate the de Broglie wavelength of a proton moving at 2.42 10 8 m/s. The wavelength of an electron moving 5.31 x 106 m/sec is 1.37 x 10-10 m or 1.37 Å. Median response time is 34 minutes and may be longer for new subjects. To start, let’s recall the mathematical relationship for the de Broglie wavelength of a particle. *Response times vary by subject and question complexity. (b) less than the kinetic energy of the particle. Learn more about our Privacy Policy. ____m. Hence, the photon’s energy is greater than the kinetic energy of the electron. A: (a) De Broglie wavelength of proton will be less . The wavelength of a 2 eV photon is given by: l = h c / E ph = 6.625 x 10-34 x 3 x 10 8 /(1.6 x 10-19 x 2) = 621 nm. Since the mass of the proton is greater than the mass of the electron, its speed is less than the speed of the electron. The factors of the proton mass in the denominator simplify and we can write that the de Broglie wavelength from the proton is Planck’s constant divided by the square root of two times the proton’s mass times its kinetic energy. 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Question 5: Which of the following is called as non-mechanical waves? Since energy is same and mass of proton is more , it's momentum will be more . Q: A small ball of mass m, initially at A, slides on the smooth circular surface ADB (see the figure be... A: since only gravitational force is acting mechanical energy can be conserved. Looking up the mass of a proton in a table, we find that it’s approximately equal to 1.67 times 10 to the negative 27th kilograms. (This is why the limiting resolution of an electron microscope is much higher than that of an optical microscope.) Wavelength of photon is depends on the source from which it emitted.. Photon of the X-ray spectra has the different wavelength than the photon of the gamma ray spectra.. proton Compton wavelength †: Numerical value: 1.321 409 855 39 x 10-15 m : Standard uncertainty: 0.000 000 000 40 x 10-15 m : Relative standard uncertainty: 3.1 x 10-10: Concise form That’s the de Broglie wavelength of a proton with this much kinetic energy. Q: A 3.00-kg object undergoes an acceleration given by a = (2.00i + 5.00j) m/s². (Mp 938.27 MeV/c2 -1.6726 1027 kg, c 3 108 m/s) 6.8 Hint: Look again at the de Broglie wavelength formula λ= h/p Remember that the momentum is p=mv Please report your results in 1015 m Then, the photon’s energy is: (a) Equal to the kinetic energy of the particle. Question 11: The operation of the electron microscope depends on the: The wave nature of the electron particles is utilized in the electron microscope. Question. F=-kx The planet’s mass is. *Response times vary by subject and question complexity. de-Broglie wavelength = (6.625×10-14)/√(2×9.11×10-31×1.6×10-17×400). The de Broglie wavelength is inversely proportional to momentum. A: conversion between C and kelvin scale is  Copyright © 2020 NagwaAll Rights Reserved. (c) greater than the kinetic energy of the particle. de Broglie wavelength λ of a particle = h /P a) since mass of proton is more than electron and speed is same , momentum of proton is more . Calculate the de Broglie wavelength of a proton moving at 2.42 ✕ 108 m/s. What is the de Broglie wavelength of a proton whose kinetic energy is 2.0 megaelectron volts? Hence, the de Broglie wavelengths of the α-particle and residual nucleus will be in the ratio = 1:1. Find answers to questions asked by student like you, Calculate the de Broglie wavelength of a proton moving at 2.42 ✕ 108 m/s. Question. The angular speed is given by, Nagwa is an educational technology startup aiming to help teachers teach and students learn. For an electron with KE = 1 eV and rest mass energy 0.511 MeV, the associated DeBroglie wavelength is 1.23 nm, about a thousand times smaller than a 1 eV photon. However, we weren’t given the proton’s speed but we were given its kinetic energy. Question 8: The de Broglie wavelength of a particle is the same as the wavelength of a photon. Question 6: Which of the following is associated with an electron microscope? So we can rewrite our equation for the de Broglie wavelength of a proton by substituting in for . It can also be determined by ta... Q: Express 200C and -50C on the Kelvin scale. Find (a) the resultant... A: The displacement vector A→can be written as, 9: An electron and a proton have the same de Broglie wavelength. The waves associated with microscopic particles when they are in motion are called matter waves. When we recall that momentum is equal to an object’s mass times its velocity, , that means we can apply the de Broglie wavelength equation to our scenario by writing that the wavelength of the proton equals Planck’s constant divided by the proton’s mass times its speed. And in general, the kinetic energy of an object, KE, is equal to one half the mass of the object times its speed squared.